Kinematics: Throwing ball up the building with unknown initial velocity

Click For Summary

Homework Help Overview

The problem involves a ball thrown upward from the top of a 65m high building, with the ball returning to the ground in 4 seconds. The original poster seeks to determine the initial velocity of the throw, the maximum height reached by the ball, and the time it takes for the ball to return to the thrower.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the possibility of breaking the problem into symmetric and asymmetric projectile motion components. Questions arise regarding the velocity of the ball as it passes the thrower on the way down and the relationship between the upward and downward velocities.

Discussion Status

Some participants have suggested considering the symmetry of projectile motion and the relationship between the initial and final velocities. The original poster expresses difficulty in starting the problem, indicating a lack of clarity on how to approach the initial velocity calculation.

Contextual Notes

The original poster notes that a similar problem provided an initial velocity, which is not the case here, adding to their confusion. There is an emphasis on the absence of air resistance in the discussion.

corporateflea
Messages
3
Reaction score
0

Homework Statement



At the top of the building that's 65m high, a guy throws a ball upward.
The ball comes back down and hits the ground in 4 seconds.

A)What is the initial velocity when the guy threw the ball?

B)What is the highest height of the ball?

C)At what time does the ball comes back to him?I'm just stumped how the hell I can start off even...

There was a homework problem very similar to this but it gave initial velocity..this problem doesn't and I don't know how to start...

Any advice would be fantastic..

(This was my first physics quiz...is it even possible to solve this?!?)

Please help...

Homework Equations



all the kinematic equations..

https://www.physicsforums.com/showpost.php?p=905663&postcount=2

The Attempt at a Solution



I can't...can't even start with A
 
Physics news on Phys.org
It should be possible. Think about splitting this problem up into a symmetric projectile motion part and an asymmetric projectile motion part (i.e. up and down are not equal). What do you know about the velocity of the ball as it passes the guy on the way down? (assuming no air resistance)
 
gamer_x_ said:
It should be possible. Think about splitting this problem up into a symmetric projectile motion part and an asymmetric projectile motion part (i.e. up and down are not equal). What do you know about the velocity of the ball as it passes the guy on the way down? (assuming no air resistance)

I tried exactly that...but no avail...

Well you can say when the ball reaches the top...and starts to fall you can do the following..

Initial V= 0 m/s
A= -10m/s/s
but that's it..

Still t and delta x are unknown...
 
you can say that, but you can also say something when the ball reaches the side of the building going downward. remember that if it's allowed to travel the same distance up as it was down, the velocity going down will be directly related to the initial velocity going up.

Perhaps you should set up your equations for a parabolic arc for a ball with an initial velocity v_i going up and coming down to the same height. What is final velocity before it hits the ground (at that height)?
 
gamer_x_ said:
you can say that, but you can also say something when the ball reaches the side of the building going downward. remember that if it's allowed to travel the same distance up as it was down, the velocity going down will be directly related to the initial velocity going up.

Perhaps you should set up your equations for a parabolic arc for a ball with an initial velocity v_i going up and coming down to the same height. What is final velocity before it hits the ground (at that height)?


So how do I go about solving the initial v?

Any step by step advice?
 

Similar threads

  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 11 ·
Replies
11
Views
5K
Replies
6
Views
6K
Replies
2
Views
4K
  • · Replies 3 ·
Replies
3
Views
5K
Replies
6
Views
4K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 9 ·
Replies
9
Views
2K
Replies
3
Views
4K
  • · Replies 3 ·
Replies
3
Views
2K