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## Homework Statement

Points A and B have electric potentials of 350 V and 160 V, respectively. When an electron released from rest at point A arrives at point C, its kinetic energy is KA.

When the electron is released from rest at point B, however, its kinetic energy when it reaches point C is KB=2KA

What is the electric potential at point C?

What is the kinetic energy KA?

## Homework Equations

KA=qV

## The Attempt at a Solution

I found the solution to the first part by doing:

2(VC-VA)=VC-VB

2VC-700=VC-160

VC=540

For the second part, I did

KA=qV

KA=(1.6022*10^-19)*(540-350)

KA=3.044*10^-17

This isn't right. Any help would be awesome :)