Kinetic Energy and Electric Potential

  • #1
ihearyourecho
61
0

Homework Statement



Points A and B have electric potentials of 350 V and 160 V, respectively. When an electron released from rest at point A arrives at point C, its kinetic energy is KA.
When the electron is released from rest at point B, however, its kinetic energy when it reaches point C is KB=2KA

What is the electric potential at point C?
What is the kinetic energy KA?


Homework Equations



KA=qV


The Attempt at a Solution



I found the solution to the first part by doing:

2(VC-VA)=VC-VB
2VC-700=VC-160
VC=540

For the second part, I did
KA=qV
KA=(1.6022*10^-19)*(540-350)
KA=3.044*10^-17

This isn't right. Any help would be awesome :)
 

Answers and Replies

  • #2
rl.bhat
Homework Helper
4,433
9
Your answer is correct.
 
  • #3
ihearyourecho
61
0
Okay, well it says it wants the answer in something that looks like eV, is that the problem there?
 
  • #4
rl.bhat
Homework Helper
4,433
9
Energy in eV = energy in Joules/charge on electron.
 
  • #5
ihearyourecho
61
0
So I would do 3.044*10^-17/1.60217646*10^-19?
Which would be KA=190?
 
  • #6
ihearyourecho
61
0
190 is the correct answer. Thanks!
 

Suggested for: Kinetic Energy and Electric Potential

  • Last Post
Replies
12
Views
920
Replies
1
Views
251
Replies
3
Views
433
  • Last Post
Replies
6
Views
420
Replies
4
Views
445
Replies
4
Views
495
  • Last Post
Replies
13
Views
430
  • Last Post
Replies
25
Views
342
Top