Kinetic Energy and Electric Potential

  • #1

Homework Statement



Points A and B have electric potentials of 350 V and 160 V, respectively. When an electron released from rest at point A arrives at point C, its kinetic energy is KA.
When the electron is released from rest at point B, however, its kinetic energy when it reaches point C is KB=2KA

What is the electric potential at point C?
What is the kinetic energy KA?


Homework Equations



KA=qV


The Attempt at a Solution



I found the solution to the first part by doing:

2(VC-VA)=VC-VB
2VC-700=VC-160
VC=540

For the second part, I did
KA=qV
KA=(1.6022*10^-19)*(540-350)
KA=3.044*10^-17

This isn't right. Any help would be awesome :)
 

Answers and Replies

  • #2
rl.bhat
Homework Helper
4,433
7
Your answer is correct.
 
  • #3
Okay, well it says it wants the answer in something that looks like eV, is that the problem there?
 
  • #4
rl.bhat
Homework Helper
4,433
7
Energy in eV = energy in Joules/charge on electron.
 
  • #5
So I would do 3.044*10^-17/1.60217646*10^-19?
Which would be KA=190?
 
  • #6
190 is the correct answer. Thanks!
 

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