# Kinetic Energy and Electric Potential

## Homework Statement

Points A and B have electric potentials of 350 V and 160 V, respectively. When an electron released from rest at point A arrives at point C, its kinetic energy is KA.
When the electron is released from rest at point B, however, its kinetic energy when it reaches point C is KB=2KA

What is the electric potential at point C?
What is the kinetic energy KA?

KA=qV

## The Attempt at a Solution

I found the solution to the first part by doing:

2(VC-VA)=VC-VB
2VC-700=VC-160
VC=540

For the second part, I did
KA=qV
KA=(1.6022*10^-19)*(540-350)
KA=3.044*10^-17

This isn't right. Any help would be awesome :)

Related Introductory Physics Homework Help News on Phys.org
rl.bhat
Homework Helper

Okay, well it says it wants the answer in something that looks like eV, is that the problem there?

rl.bhat
Homework Helper
Energy in eV = energy in Joules/charge on electron.

So I would do 3.044*10^-17/1.60217646*10^-19?
Which would be KA=190?

190 is the correct answer. Thanks!