# Kinetic Energy and Electric Potential

ihearyourecho

## Homework Statement

Points A and B have electric potentials of 350 V and 160 V, respectively. When an electron released from rest at point A arrives at point C, its kinetic energy is KA.
When the electron is released from rest at point B, however, its kinetic energy when it reaches point C is KB=2KA

What is the electric potential at point C?
What is the kinetic energy KA?

KA=qV

## The Attempt at a Solution

I found the solution to the first part by doing:

2(VC-VA)=VC-VB
2VC-700=VC-160
VC=540

For the second part, I did
KA=qV
KA=(1.6022*10^-19)*(540-350)
KA=3.044*10^-17

This isn't right. Any help would be awesome :)

Homework Helper

ihearyourecho
Okay, well it says it wants the answer in something that looks like eV, is that the problem there?

Homework Helper
Energy in eV = energy in Joules/charge on electron.

ihearyourecho
So I would do 3.044*10^-17/1.60217646*10^-19?
Which would be KA=190?

ihearyourecho
190 is the correct answer. Thanks!