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## Homework Statement

A hoop with mass m= 10 kg, radius r=0.6 m, and moment of inertia I=mr^2 is rolling without slipping with a linear velocity of 8.5 m/s. What is the total kinetic energy (in J).

## Homework Equations

K=1/2 m v^2

Kr=1/2 I ω^2

## The Attempt at a Solution

The kinetic energy of the object is

K = 1/2 m v^2

K = 1/2 (10) (8.5) = 42.5 J

The rotational kinetic energy

Kr = 1/2 (10 * 0.6^2) (8.5/0.6)^2 = 361.25 J

Total kinetic energy

42.5 + 361.25 = 403.75 J

I am not sure about my solution since the answer I end up with is not included in the choices of the question.