Kinetic Energy and Time Problem

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jtim36
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Homework Statement


A ball with mass m projected horizontally o the end of a table with an initial kinetic energy K. At a time t after it leaves the end of the table it has kinetic energy 3K. What is t? Neglect air resistance.
(answer: (2/g)(√K/m)

Homework Equations


E = 1/2 mv^2


The Attempt at a Solution


I understand what the problem is asking, but I don't get how to relate time and kinetic energy
 
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x = vo(t) + 1/2at^2
v^2 = v0^2 + 2ah

Okay, so does that mean the final velocity was tripled then? and I apply the above equations?
 
jtim36 said:
x = vo(t) + 1/2at^2
v^2 = v0^2 + 2ah

Okay, so does that mean the final velocity was tripled then? and I apply the above equations?

No. Not tripled. Think conservation of energy. You have to gain energy 2K by losing potential energy mgh. Put time into it by figuring how long it takes to fall a distance h with zero initial vertical velocity.