1. The problem statement, all variables and given/known data When a 7 3 Li nucleus is bombarded with protons α particles emerge.Calculate the kinetic energy of the alpha particle assuming the kinetic energy of the bombarding proton to be negligible. Given M (7 3 Li)=7.016004a.m.u. M (p)=1.007826a.m.u and M (α)=4.002603a.m.u. 2. Relevant equations 7 3 Li + 1 1H --> 24 2He Q = (M Li + MH -2Mα)931.5MeV....1 Kα=n= [MαQ + Kp(Mα - mp)]/2Mα....2 3. The attempt at a solution Using equation 1 Q=(7.016004+1.007826- 2×4.002603) 931.5 =17.35MeV It is given that Kp~0 so Kα= Q/2 =8.675MeV What do you people think about my solution methods used? The numerical values are matching approximately with the given answers in the text book by the way.