Kinetic energy of alpha particle in cockroft walton experiment.

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SUMMARY

The discussion focuses on calculating the kinetic energy of an alpha particle produced in the Cockcroft-Walton experiment when a lithium-7 nucleus is bombarded with protons. The relevant masses are M(7 3 Li) = 7.016004 a.m.u, M(p) = 1.007826 a.m.u, and M(α) = 4.002603 a.m.u. The calculation yields a kinetic energy of the alpha particle (Kα) as 8.675 MeV, derived from the equation Q = (M Li + M H - 2M α)931.5 MeV, resulting in Q = 17.35 MeV.

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  • Knowledge of the Cockcroft-Walton accelerator and its applications
  • Proficiency in using atomic mass units (a.m.u) for calculations
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Homework Statement


When a 7 3 Li nucleus is bombarded with protons α particles emerge.Calculate the kinetic energy of the alpha particle assuming the kinetic energy of the bombarding proton to be negligible. Given M (7 3 Li)=7.016004a.m.u. M (p)=1.007826a.m.u and M (α)=4.002603a.m.u.

Homework Equations


7 3 Li + 1 1H --> 24 2He
Q = (M Li + MH -2Mα)931.5MeV...1

Kα=n= [MαQ + Kp(Mα - mp)]/2Mα...2
[/B]

The Attempt at a Solution


Using equation 1 Q=(7.016004+1.007826- 2×4.002603) 931.5 =17.35MeV
It is given that Kp~0 so Kα= Q/2 =8.675MeV
What do you people think about my solution methods used? The numerical values are matching approximately with the given answers in the textbook by the way.

[/B]
 
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Sure, looks good.

What does equation 2 mean? It is not necessary anyway.
 

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