(adsbygoogle = window.adsbygoogle || []).push({}); 1. Ultraviolet light with a wavelength of 60.0 nm shines on a gas of hydrogen atoms in their ground states. Some of the atoms are ionized by the light. What is the kinetic energy of the electrons that are freed in this process?

2. E_{n}= n^{2}h^{2}/8mL^{2}

3. To get L, I solved lambda = 2L/n with n = 1, obtaining L = 3*10^{-8}m. Plugging to the E_{n}equation, using n =1 and h = 4.14*10^{-15}eVs, I obtain an incorrect answer. I tried using both the Js and EvS numbers for h, but I was wrong either way...

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# Kinetic energy of an ionized electron

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