iuchem16
- 4
- 0
An ion of 64Zn30+ with an initial kinetic energy of 9.88 keV is accelerated across a potential difference of 277 Volts. What is its kinetic energy after acceleration (in keV)?
An ion of 64Zn30+ with an initial kinetic energy of 9.88 keV is accelerated across a potential difference of 277 Volts. The energy transferred to the ion due to this potential difference is calculated as 277 eV per unit charge. To find the final kinetic energy after acceleration, one must multiply the charge of the ion by the potential difference and add this value to the initial kinetic energy, resulting in a definitive calculation of the ion's new kinetic energy.
PREREQUISITESStudents and professionals in physics, particularly those studying electromagnetism, particle acceleration, and energy transfer in charged particles.
iuchem16 said:An ion of 64Zn30+ with an initial kinetic energy of 9.88 keV is accelerated across a potential difference of 277 Volts. What is its kinetic energy after acceleration (in keV)?