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iuchem16
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An ion of 64Zn30+ with an initial kinetic energy of 9.88 keV is accelerated across a potential difference of 277 Volts. What is its kinetic energy after acceleration (in keV)?
iuchem16 said:An ion of 64Zn30+ with an initial kinetic energy of 9.88 keV is accelerated across a potential difference of 277 Volts. What is its kinetic energy after acceleration (in keV)?
The kinetic energy of ions accelerated across a potential difference is the energy gained by the ions as they move through a potential difference, or voltage, due to the electric field. This energy is related to the mass and velocity of the ions and is measured in joules (J).
The kinetic energy of ions can be calculated using the equation KE = ½mv², where m is the mass of the ion and v is its velocity. This equation is derived from the more general equation for kinetic energy, KE = ½mv², which applies to all moving objects.
The kinetic energy of ions accelerated across a potential difference is affected by the mass and velocity of the ions. In addition, the strength of the electric field and the distance the ions travel through the potential difference also impact the kinetic energy.
The kinetic energy of ions is directly proportional to the potential difference. This means that as the potential difference increases, so does the kinetic energy of the ions. This relationship is described by the equation KE = qV, where q is the charge of the ion and V is the potential difference.
The kinetic energy of ions is used in a variety of scientific research applications, such as in mass spectrometry to determine the mass and charge of ions, and in particle accelerators to study the properties of subatomic particles. It is also relevant in fields such as plasma physics and materials science, where ions play a significant role.