Hello. It's not a homework but it is kind of exercise. I was wondering what's the kinetic energy of water flow (for a certain amount) from a faucet. But I'm not sure if I got it right. So I counted how much volume of water is dropped in 30 seconds. It turned out it's about 5.6liters. m=5.6kg // as 1 liter of water is almost 1kg t=30s l=1.256*10E-3m^2 // area of water dropping, cross-sectional area Vol=5.6*10E-3m^3 // volume of water Ek=mv^2/2 v=s/t s=Vol/l s=5.6*10E-3/1.256*10E-3 [m^3/m^2=m] s=4.45m v=4.45m/30s v=0.148m/s Ek=5.6kg*(0.148m/s)^2/2 Ek=5.6*0.0219kg*m^2/s^2 Ek=0.0613J Ek=61.3mJ So I got that pouring 5.6 liters of water realeses 61.3 milijoules. I thought it woul be a little more when I see water dropping at high pressure. Did I get that right? I don't know if I posted it in the right section. I'm ew here. It's not a homework but I'm afraid I would get my post deleted if I posted it in classic physics. Sorry I didn't use the template provided,but they didn't fit my post too good.