Kinetic Energy Related to Potential

[Noms]

Object dropped from rest at h₀meters. At what height, h₁, will K=2U? g=9.8m/s²K=2U
E_T=K-U
(.5)mv²=2(mgh)
v²=gh
(v²)/g=h

Thanks. :)

 

[Andrew Mason]

Object dropped from rest at h₀meters. At what height, h₁, will K=2U? g=9.8m/s²


K=2U
E_T=K-U



(.5)mv²=2(mgh)
v²=gh
(v²)/g=h

Thanks. :)

Your question does not make sense. Please give us the entire question exactly as you were given it.

AM

 

[mantxi]

Before dropping the object the total energy is E = K + U = 0+mgh.

After falling, the total energy will be E' = K' + U' = 2U' + U' = 3U'

As we know, E = E'

Then, mgh = 3mgh' --> h' = 1/3 h

 

[Noms]

AM- Sorry I wasn't clear enough for you, but thanks for looking it over,

M- That's just what I needed. :)