Kinetic Energy Vs. Potential Energy confusion.

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Homework Help Overview

The discussion revolves around a physics problem involving a car decelerating to avoid an accident. The problem is set in the context of kinetic energy and work done during braking, with specific parameters provided such as weight, deceleration, and distance to a hazard.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the application of conservation of energy and kinematic equations to determine the work done in stopping the car. Questions arise regarding the appropriate signs for acceleration and the relevance of potential energy in this scenario.

Discussion Status

Some participants have offered guidance on using energy conservation principles and kinematic equations, while others express confusion about the signs and the relevance of potential energy. There is a mix of attempts to clarify concepts and explore different methods without reaching a consensus.

Contextual Notes

Participants note the absence of potential energy changes in the problem and discuss the implications of constant acceleration. There is also mention of specific homework constraints regarding the approach to solving the problem.

teriblekelly
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Homework Statement



A car and driver weighing 5530 N passes a
sign stating "Bridge Out 25.5 m Ahead." She
slams on the brakes, and the car decelerates
at a constant rate of 13.7 m/s^2 :
The acceleration of gravity is 9.8 m/s^2 :
What is the magnitude of the work done
stopping the car if the car just stops in time
to avoid diving into the water? Answer in
units of J.


Homework Equations


This is where I'm stuck. In class today we learned about Conservation of Energy and I don't know if that applies here.
I know there is constant acceleration in forward direction so I could use Kinematics but I don't know where to go from there I'm confused as to what sign to designate to 13.7 m/s^2.
So far I have: Vf^2=Vo^2+2a(deltaX)
0=Vo^2+2(-13.7 m/s^2)(25.5m)
Vo^2=698.7
Vo=26.432934 m/s

The Attempt at a Solution

 
Last edited:
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Anyone out there to help?
 
If you want to solve it with energy, I suggest beginning with all the pertinent conditions at the beginning and setting them equal to those at the end (think what kinetic will be) plus the energy lost by heat in the breaks, which is what you're looking for.
 
Nevermind I just figure out the entire problem.
 
teriblekelly said:

Homework Statement



A car and driver weighing 5530 N passes a
sign stating "Bridge Out 25.5 m Ahead." She
slams on the brakes, and the car decelerates
at a constant rate of 13.7 m/s^2 :
The acceleration of gravity is 9.8 m/s^2 :
What is the magnitude of the work done
stopping the car if the car just stops in time
to avoid diving into the water? Answer in
units of J.


Homework Equations


This is where I'm stuck. In class today we learned about Conservation of Energy and I don't know if that applies here.
I know there is constant acceleration in forward direction so I could use Kinematics but I don't know where to go from there I'm confused as to what sign to designate to 13.7 m/s^2.
So far I have: Vf^2=Vo^2+2a(deltaX)
0=Vo^2+2(-13.7 m/s^2)(25.5m)
Vo^2=698.7
Vo=26.432934 m/s

The Attempt at a Solution

using the kinematic equation gets you the initial velocity of the car, which you have correctly done. Now if you want to use conservation of energy,write down that equation and solve for the work done by the braking force. PE does not come into the equation, since there is no PE change. (It's perhaps a bit easier to use Newton 2, but that depends on how you are asked to solve this problem.
 

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