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Kinetic Energy Vs. Potential Energy confusion.

  • #1

Homework Statement



A car and driver weighing 5530 N passes a
sign stating "Bridge Out 25.5 m Ahead." She
slams on the brakes, and the car decelerates
at a constant rate of 13.7 m/s^2 :
The acceleration of gravity is 9.8 m/s^2 :
What is the magnitude of the work done
stopping the car if the car just stops in time
to avoid diving into the water? Answer in
units of J.


Homework Equations


This is where I'm stuck. In class today we learned about Conservation of Energy and I don't know if that applies here.
I know there is constant acceleration in forward direction so I could use Kinematics but I don't know where to go from there I'm confused as to what sign to designate to 13.7 m/s^2.
So far I have: Vf^2=Vo^2+2a(deltaX)
0=Vo^2+2(-13.7 m/s^2)(25.5m)
Vo^2=698.7
Vo=26.432934 m/s

The Attempt at a Solution

 
Last edited:

Answers and Replies

  • #2
Anyone out there to help?
 
  • #3
TMM
92
0
If you want to solve it with energy, I suggest beginning with all the pertinent conditions at the beginning and setting them equal to those at the end (think what kinetic will be) plus the energy lost by heat in the breaks, which is what you're looking for.
 
  • #4
Nevermind I just figure out the entire problem.
 
  • #5
PhanthomJay
Science Advisor
Homework Helper
Gold Member
7,135
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Homework Statement



A car and driver weighing 5530 N passes a
sign stating "Bridge Out 25.5 m Ahead." She
slams on the brakes, and the car decelerates
at a constant rate of 13.7 m/s^2 :
The acceleration of gravity is 9.8 m/s^2 :
What is the magnitude of the work done
stopping the car if the car just stops in time
to avoid diving into the water? Answer in
units of J.


Homework Equations


This is where I'm stuck. In class today we learned about Conservation of Energy and I don't know if that applies here.
I know there is constant acceleration in forward direction so I could use Kinematics but I don't know where to go from there I'm confused as to what sign to designate to 13.7 m/s^2.
So far I have: Vf^2=Vo^2+2a(deltaX)
0=Vo^2+2(-13.7 m/s^2)(25.5m)
Vo^2=698.7
Vo=26.432934 m/s

The Attempt at a Solution

using the kinematic equation gets you the initial velocity of the car, which you have correctly done. Now if you want to use conservation of energy,write down that equation and solve for the work done by the braking force. PE does not come into the equation, since there is no PE change. (It's perhaps a bit easier to use Newton 2, but that depends on how you are asked to solve this problem.
 

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