1. The problem statement, all variables and given/known data A crate is pushed at constant velocity across a rough, horizontal surface by a push force P. The crate has a weight of 73N. Coefficient of kinetic friction between the crate and the floor is 0.41. Vector force P points at an angle of 37 degrees below the horizontal. What is the magnitude of the normal force? 2. Relevant equations fk = μkN constant velocity indicates v0=vfinal and therefore a=0 no movement in the y direction, therefore ƩFy=0 These are random things that I have found online but I'm not sure if they're true: Fcosθ=f (The horizontal component of the push force is equivalent to to friction) 3. The attempt at a solution The problem is, I don't have the magnitude of the push force. I don't know where to go from here, but I have tried many things. To find the kinetic friction: fk = μkN =(0.41)(73N) =29.9N Using Fcosθ=f, I assume that 29.9N is the horizontal component of the push force. I then find the vertical component of the push force: Py=29.9N*tan37 Py=19.6N I then add this to the weight to find the Normal Force: 73+19.6=92.6N The Normal Force is not 92.6N. This problem is from an exam I failed last semester, and I have the correct answer now, but I can't get to it. Thank you in advance, for anyone who can help me out.