Kinetic, Potential, and Mechanical Energy

AI Thread Summary
The discussion focuses on calculating the kinetic, potential, and mechanical energies of a 0.420 kg ball thrown vertically upward at an initial speed of 12.1 m/s. Participants suggest using the formulas for kinetic energy (K = 1/2 mv^2) and gravitational potential energy (U = mgh) to solve the problem. The initial potential energy is set to zero, and the energies need to be calculated at the initial position, at 1.75 m above the initial position, and at the maximum height. The conversation highlights the need for clarity on the relevant equations of motion. Overall, the thread emphasizes the importance of understanding kinetic and potential energy calculations in physics.
BreezyHani
Messages
4
Reaction score
0

Homework Statement



A .420kg ball is throw vertically upward at an intial sped o 12.1 m/s. If the initial potential energy is taken as zero find the bal's kinetic, potential, and mecanical energies a.) at its intial position b.) at 1.75m above the initial position, and c.) at its maximum height



Homework Equations





The Attempt at a Solution


I don't know what formula to use guys :( my brain is hurting from organic chem overload.
 
Physics news on Phys.org
BreezyHani said:

Homework Statement



A .420kg ball is throw vertically upward at an intial sped o 12.1 m/s. If the initial potential energy is taken as zero find the bal's kinetic, potential, and mecanical energies a.) at its intial position b.) at 1.75m above the initial position, and c.) at its maximum height



Homework Equations





The Attempt at a Solution


I don't know what formula to use guys :( my brain is hurting from organic chem overload.

Expressions for Kinetic energy and Gravitational Potential energy would be a good start.
You may want to use the standard equations of motion, but KE and PE are all you really need.
 
Kinetc energy I use the: K=1/2mv^2 right? gravitational i use the U=mgy ?
 
BreezyHani said:
Kinetc energy I use the: K=1/2mv^2 right? gravitational i use the U=mgy ?

Those formulae will work
 
ok thank you!
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
Thread 'Trying to understand the logic behind adding vectors with an angle between them'
My initial calculation was to subtract V1 from V2 to show that from the perspective of the second aircraft the first one is -300km/h. So i checked with ChatGPT and it said I cant just subtract them because I have an angle between them. So I dont understand the reasoning of it. Like why should a velocity be dependent on an angle? I was thinking about how it would look like if the planes where parallel to each other, and then how it look like if one is turning away and I dont see it. Since...
Thread 'Correct statement about a reservoir with an outlet pipe'
The answer to this question is statements (ii) and (iv) are correct. (i) This is FALSE because the speed of water in the tap is greater than speed at the water surface (ii) I don't even understand this statement. What does the "seal" part have to do with water flowing out? Won't the water still flow out through the tap until the tank is empty whether the reservoir is sealed or not? (iii) In my opinion, this statement would be correct. Increasing the gravitational potential energy of the...
Back
Top