Kinetics/Motion in 2D/Energy question

  • #1

Homework Statement


A 12V car battery is capable of storing 3.51 kWh of electric energy. For a certain electric car to maintain a speed of 48.3 km/hr, it must develop 10.7 kW of power. If this car is run by 11 batteries which are 90.5% efficient, how far can this car travel, at the desired speed, between recharges?
V= 48.3 m/s (yes constant motion)
P=10700W
efficiency= 90.5%
Each battery capacity= 3510W
Uses 11 batteries

Homework Equations


E= (Wo / Wi ) *100[/B]
E= .5 * m * v^2
W= P*t

The Attempt at a Solution


1. Since its going at a constant velocity, i can find the mass. Using the Energy kinetic formula.
2.Finding the mass i can plug it into the efficiency formula to get its work output.
3. its using 11 batteries that are 90.5% efficient. So on the denominator of the efficiency formula it would be 11* 3510W because each capacity is 3.51kWh.
5.the numerator would be the Energy kinetic formula * 100 and then the efficiency would be 90.5%
6. Getting the time i could multiply it with the velocity to get its distance?
 

Attachments

Answers and Replies

  • #2
haruspex
Science Advisor
Homework Helper
Insights Author
Gold Member
2020 Award
35,591
6,455
Since its going at a constant velocity, i can find the mass. Using the Energy kinetic formula.
Since it's at constant velocity, the KE is constant. The energy from the batteries is not being used to add to KE, so it won't tell you the mass. Neither KE nor the mass are of interest here.
You are told how much power it needs to supply to the wheels, and you know the efficiency, so how much power must be drawn from the batteries?
How long can the batteries supply that power for?
 
  • #3
Since it's at constant velocity, the KE is constant. The energy from the batteries is not being used to add to KE, so it won't tell you the mass. Neither KE nor the mass are of interest here.
You are told how much power it needs to supply to the wheels, and you know the efficiency, so how much power must be drawn from the batteries?
How long can the batteries supply that power for?
Okay ignoring the kinetic formula, my bad wasnt thinking straight. Re doing the effieciency formula it would be 90.5%= (10700W*100%/ (11* (3.51kWh*3.6E6)t)
 
  • #4
Okay ignoring the kinetic formula, my bad wasnt thinking straight. Re doing the effieciency formula it would be 90.5%= (10700W*100%/ (11* (3.51kWh*3.6E6)t)
Using this formula we're able to calculate how long the batteries will last at the power to run the car.?
 
  • #5
haruspex
Science Advisor
Homework Helper
Insights Author
Gold Member
2020 Award
35,591
6,455
Okay ignoring the kinetic formula, my bad wasnt thinking straight. Re doing the effieciency formula it would be 90.5%= (10700W*100%/ (11* (3.51kWh*3.6E6)t)
Close, but if you check the dimensions you'll find it doesn't make sense. You have power/(energy*time).
 

Related Threads on Kinetics/Motion in 2D/Energy question

  • Last Post
Replies
2
Views
959
  • Last Post
Replies
3
Views
3K
  • Last Post
Replies
3
Views
1K
  • Last Post
Replies
3
Views
2K
  • Last Post
Replies
1
Views
1K
Replies
1
Views
2K
  • Last Post
Replies
8
Views
3K
Replies
1
Views
590
  • Last Post
Replies
2
Views
9K
  • Last Post
Replies
9
Views
1K
Top