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Curious&TheNon

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## Homework Statement

A 12V car battery is capable of storing 3.51 kWh of electric energy. For a certain electric car to maintain a speed of 48.3 km/hr, it must develop 10.7 kW of power. If this car is run by 11 batteries which are 90.5% efficient, how far can this car travel, at the desired speed, between recharges?

V= 48.3 m/s (yes constant motion)

P=10700W

efficiency= 90.5%

Each battery capacity= 3510W

Uses 11 batteries

## Homework Equations

E= (Wo / Wi ) *100[/B]

E= .5 * m * v^2

W= P*t

## The Attempt at a Solution

1. Since its going at a constant velocity, i can find the mass. Using the Energy kinetic formula.

2.Finding the mass i can plug it into the efficiency formula to get its work output.

3. its using 11 batteries that are 90.5% efficient. So on the denominator of the efficiency formula it would be 11* 3510W because each capacity is 3.51kWh.

5.the numerator would be the Energy kinetic formula * 100 and then the efficiency would be 90.5%

6. Getting the time i could multiply it with the velocity to get its distance?