Kirchhoff's Rule: Solving Two Equations

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SUMMARY

This discussion focuses on applying Kirchhoff's Rules to derive two independent equations for a circuit. The equations established are: emf2 - I1R3 - I2R2 - I1R1 = 0 and emf1 - I3R2 + I2R2 = 0. The confusion regarding the terms I1R1 versus I4R1 is clarified by noting that R1, emf2, and R3 are in series, thus the current I1 flows through all of them. Additionally, the positive sign in the term +I2R2 is explained by the direction of current flow and voltage gain when traversing the resistor.

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  • Understanding of Kirchhoff's Voltage Law (KVL)
  • Familiarity with Ohm's Law (V=IR)
  • Basic circuit analysis techniques
  • Knowledge of series and parallel circuit configurations
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Homework Statement


write two independent equations using kirchhoff rule to describe the circuit.


Homework Equations



V=IR
Emf = IR

The Attempt at a Solution



The answer is
emf2 -I1R3-I2R2-I1R1 = 0
(ok i have questions here: why is it I1R1? shouldn't it be I4R1?)
and
emf1-I3R2+I2R2 = 0

(my question here is why is it +I2R2, why wouldn't u put -I2R2? or does it depend on which way you set up current through R2?)
 

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soupastupid said:
(ok i have questions here: why is it I1R1? shouldn't it be I4R1?)

There is no I4 that I can see. In any case, R1, emf2, and R3 are all in series, so the current has to be the same through all of them (and that current is I1 in this diagram)

soupastupid said:
(my question here is why is it +I2R2, why wouldn't u put -I2R2? or does it depend on which way you set up current through R2?)

When you go around the loop, you're moving across the resistor from bottom to top, which is the opposite direction from the direction of the current through that resistor. The current flows from top to bottom, which means that the top side is more positive than the bottom side. So if you move from bottom to top, you gain voltage.
 

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