Ksp and precipitation of carbonates

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SUMMARY

The discussion centers on the solubility product constant (Ksp) and its role in predicting the precipitation of carbonates, specifically strontium and barium carbonates. Participants clarify that lower Ksp values indicate greater insolubility, and that precipitation can be determined by comparing ion concentrations to Ksp values. The conclusion reached is that strontium and barium carbonates will precipitate when ion concentrations exceed their respective Ksp thresholds.

PREREQUISITES
  • Understanding of solubility product constant (Ksp)
  • Knowledge of ion concentrations in solutions
  • Familiarity with carbonate chemistry
  • Ability to perform dilution calculations
NEXT STEPS
  • Learn how to calculate Ksp values for various compounds
  • Study the principles of ionic equilibrium in solutions
  • Explore the effects of dilution on solubility
  • Investigate the precipitation reactions of other metal carbonates
USEFUL FOR

Chemistry students, educators, and professionals involved in analytical chemistry or materials science who need to understand carbonate solubility and precipitation processes.

TT0
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Homework Statement


Screen Shot 2016-07-04 at 1.46.53 PM.png


Homework Equations

The Attempt at a Solution


The lower the Ksp, the more insoluble. Therefore, I chose B since strontium and barium carbonates have the lowest Ksp. However, the question asks which carbonate will precipitate and I know that all carbonates are insoluble. Can someone explain to me what did I think wrong?

Cheers!
 
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Why don't you calculate instead of guessing?
 
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Why don't you calculate instead of guessing?

Sorry, but I can't see what to calculate. Could you please tell me where can I calculate something?

Thanks!
 
You are given Ksp, you are given concentrations - you can easily check whether the precipitate should form or not. If you don't see how - read about solving Ksp related problems.

Don't forget about dilution.
 
I see, after calculating, strontium and barium carbonate won't dissolve as the molarity of the ions in the solution exceed the amount that will dissolve. Is the answer B?

Thanks
 
Yes.
 
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