Ladder question (Static equilibrium)

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SUMMARY

The discussion centers on calculating the maximum height an 800 N person can climb on an 8.0 m ladder, which rests against a smooth vertical wall at a 50.0° angle. The ladder has a weight of 200 N and a static friction coefficient of 0.60. Participants emphasize the importance of considering both friction and normal force when setting up torque equations, particularly using the base of the ladder as the pivot point to analyze forces in static equilibrium.

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  • Understanding of static equilibrium principles
  • Knowledge of torque calculations
  • Familiarity with friction coefficients
  • Basic mechanics of forces and moments
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  • Explore the concept of normal force in static scenarios
  • Review examples of ladder problems in physics
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bjgawp
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Here's my problem:
An 8.0 m, 200 N ladder rests against a smooth vertical wall. The coefficient of static friction between the ladder and the ground is 0.60, and the ladder makes a 50.0° angle with the ground. How far up the ladder can an 800 N person climb before the ladder begins to slip?

The problem is that I cannot set up the equation for the torques.
Tnet = 0
If we use the bottom of the ladder as our pivot point, we won't have to worry about friction and the normal force - leaving the 200 N ladder, the 800 N person, and the force provided from the wall (I may be wrong). But, after looking through my notes, I am lost on setting up the equation for the torques. Any help would be appreciated.

Thanks in advance!
 
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Have you taken the fact that the forces need to be in equilibrium into account?
 
bjgawp said:
...If we use the bottom of the ladder as our pivot point, we won't have to worry about friction and the normal force...

It's quite the opposite - you should worry about friction and the normal force.
 

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