Laplace / inverse laplace transform

Click For Summary
SUMMARY

The discussion focuses on the application of the Laplace transform to solve differential equations involving delta functions. Specifically, the transformation of the expression $$\frac{-1}{s+1} + \frac{2}{s-3}$$ is analyzed, revealing that the correct solution includes step functions due to the presence of delta functions on the right-hand side of the equation. The participants clarify that the solutions $$-e^{-t} + 2e^{3t}$$ are valid only under certain conditions, necessitating the use of Heaviside step functions to define the solution's domain accurately.

PREREQUISITES
  • Understanding of Laplace transforms and their properties
  • Familiarity with differential equations and their solutions
  • Knowledge of delta functions and their significance in mathematical analysis
  • Basic grasp of Heaviside step functions and their applications
NEXT STEPS
  • Study the properties of delta functions and their derivatives in the context of Laplace transforms
  • Learn about Heaviside step functions and their role in defining piecewise solutions
  • Explore advanced applications of Laplace transforms in solving non-homogeneous differential equations
  • Investigate the implications of initial conditions in the context of Laplace transform solutions
USEFUL FOR

Mathematicians, engineers, and students studying differential equations, particularly those interested in the applications of Laplace transforms and delta functions in solving complex problems.

goohu
Messages
53
Reaction score
3
View attachment 9453

Problem: Find a (limited?) solution to the diff eq.

View attachment 9454
At the end of the solution, when you transform $$\frac{-1}{s+1} + \frac{2}{s-3}$$
why doesn't it become $$-e^{-t} + 2e^{3t} $$, t>0 ?
 

Attachments

  • prob.JPG
    prob.JPG
    6 KB · Views: 179
  • Sol.JPG
    Sol.JPG
    11.9 KB · Views: 169
Physics news on Phys.org
That would be correct if the right hand side of the equation were 0. But the delta functions on the right mean that those are correct only for x greater than certain values so the step functions are needed.
 
What values are those and how are the step functions used?
 
Do you know what "\delta(x)" and "\delta'(x)" mean?
 

Similar threads

  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 7 ·
Replies
7
Views
6K
  • · Replies 17 ·
Replies
17
Views
3K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 5 ·
Replies
5
Views
5K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 4 ·
Replies
4
Views
11K
  • · Replies 1 ·
Replies
1
Views
10K