now say we have cos^2(3t), how would you go about computing it with the 3t?(adsbygoogle = window.adsbygoogle || []).push({});

i can manage cos^2(t) but i'm not sure how to take it that one step further

in the link below is what i've managed so far..

SOLVED

I worked it out.

If anyone's interested in the future, Just start it off as cos^2(t). Solve it all the way through using the identity (1/2)(cos2t+1) <------- this identity can be split up and solved using your standard Laplace identities.

Then identify the 3t from cos^2(3t). Realize that it's 3*ANGLE so multiply your integers in your final laplace transform of cos^2(t) by 3^2=9.

Your two integers should end up as 18 in the numerator and 36 in your denominator.

Hope this helps.

-chief10

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# Laplace Transform of squared trig functions help?

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