Laplace transform of step function

In summary, the conversation discusses finding the Laplace transform of the function f(t) = { 0 t<2, (t-2)^2 t>=2. The individual is struggling with solving the problem and is seeking help. They mention trying to put the function into a form that can be looked up in a table, but are unsure if they have the correct function. The solution is suggested to be done through direct substitution and using integration by parts.
  • #1
chota
22
0
this isn't homework, this is just general knowledge and i can't figure it out.. please help, thx

Find the Laplace transform of the given function:

f(t) = { 0 t<2, (t-2)^2 t>=2

I tried working it out and this is where i get stuck

f(t) = (t-2)^2 * u(t-2)

I am not sure if I got the write function for f(t), but if I did, I am not sure how to go on with solving this.
Any help is appreciated, Thank YOu
Chota
 
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  • #2
Are you trying to put this into a form that you can look it up in a table? Your statement "I am not sure if I got the right function for f(t)" is confusing since it's already given.

Seems to me that you can do this by direct substutition into the definition of the transform:

[tex]
F(s) = \int_0^\infty e^{-st} f(t) dt
[/tex]

put in your f(t), starting your integral at t=2, make a t-2 change of vars, and integrate by parts a couple times.
 
  • #3


Hi Chota,

The Laplace transform of a step function u(t-a) is 1/s * e^(-as), where s is the variable in the Laplace transform. In your case, the step function is u(t-2), so the Laplace transform of this step function would be 1/s * e^(-2s).

Now, for the function (t-2)^2, we can use the Laplace transform property of differentiation to solve for its Laplace transform. The property states that the Laplace transform of the derivative of a function is equal to s times the Laplace transform of the function minus the initial value of the function at t=0. In this case, the derivative of (t-2)^2 is 2(t-2). So, the Laplace transform of (t-2)^2 would be 2/s * e^(-2s) - 2 * 1/s * e^(-2s) = 2/s^2 * e^(-2s).

Combining these two results, the Laplace transform of f(t) would be:

F(s) = 1/s * e^(-2s) + 2/s^2 * e^(-2s)

I hope this helps! Let me know if you have any other questions. Good luck!

 

Related to Laplace transform of step function

1. What is the Laplace transform of a step function?

The Laplace transform of a step function is a mathematical tool used to convert a function from the time domain to the frequency domain. It is defined as the integral of the function multiplied by the exponential function e^(-st), where s is a complex number. In the case of a step function, the Laplace transform is equal to 1/s, where s is the complex frequency variable.

2. What is the significance of the Laplace transform of a step function?

The Laplace transform of a step function is significant because it allows us to analyze the behavior of a function in the frequency domain. This is useful in many branches of science and engineering, as it simplifies the analysis of systems with complex inputs or outputs. It also helps in solving differential equations, as the Laplace transform can convert them into algebraic equations.

3. How is the Laplace transform of a step function calculated?

The Laplace transform of a step function can be calculated using the Laplace transform definition, which involves taking the integral of the function multiplied by the exponential function e^(-st). In the case of a step function, the integral can be evaluated easily, resulting in a simple function of the complex frequency variable s. Alternatively, there are tables and software programs available that can provide the Laplace transform of common functions, including the step function.

4. What is the inverse Laplace transform of a step function?

The inverse Laplace transform of a step function is the function itself. In other words, the inverse Laplace transform of 1/s is the step function. This can be easily verified by taking the Laplace transform of the step function and then applying the inverse Laplace transform.

5. What are the applications of the Laplace transform of a step function?

The Laplace transform of a step function has various applications in different fields of science and engineering. It is commonly used in control systems, communication systems, signal processing, and electrical circuits. It is also used in solving differential equations, which are common in physics, engineering, and mathematics. Additionally, the Laplace transform is a fundamental tool in the study of linear systems and is crucial in understanding their stability and response to different inputs.

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