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Large nuclei to proton ratios reduce repulsion in a nucleus

  1. Sep 14, 2015 #1
    Hi, I am new here.
    I am just reading over my notes for stable and unstable nuclei and I came across this sentence: 'Large nuclei require a higher neutron proton ratio as this adds more nuclear attraction without adding repulsion'. I was wondering why the large ratio would reduce repulsion?
    Thank you for reading.
     
  2. jcsd
  3. Sep 14, 2015 #2

    DEvens

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    It allows the protons, with the electric charge, to be farther apart.
     
  4. Sep 14, 2015 #3
    Thank you very much for your help. I understand now.
     
  5. Sep 15, 2015 #4

    Meir Achuz

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    "Without adding repulsion" does not mean 'reducing' repulsion.
    Adding a proton increases nuclear attraction, but also increases electrostatic energy.
    Adding a neutron increases the nuclear attraction with no increase in electrostatic repulsion.
     
  6. Sep 15, 2015 #5

    mfb

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    In this case it does. It increases the effective distances between protons.
     
  7. Sep 15, 2015 #6
    Thank you
     
  8. Sep 15, 2015 #7
    Thank you for you help
     
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