Latus rectum for the non-mathematician

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SUMMARY

The discussion centers on calculating the length of a chord (latus rectum) for an elliptical shape with a major axis of 165 and a minor axis of 80, where the axes intersect off-center at coordinates (100, 40). A proposed algorithm involves using the equations of two ellipses: Left side: x²/652 + y²/402 = 1 and Right side: x²/100² + y²/402 = 1. The length of the chord is determined by the formula length = 2 * sqrt(402(1 - x²/652)), where x represents the distance from the intersection of the axes.

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bhnh
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I'm hoping someone can help me with this question. I'm an animator; the last math course I took was 40 years ago:bugeye:.

I have an elliptical shape wherein the major and minor axes intersect off-center, so I've got an egg shape (major axis=165, minor axis =80, intersection at 100,40). I have a line perpendicular to the major axis which can be positioned at any point along the major axis. What I need is a basic algorithm to figure the length of the resulting chord (latus rectum?).

I wouldn't want to admit to being desperate, but I am, kind of. Any help would be immensely appreciated.

Thanks!
 

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I suppose your shape is two ellipses joined at the minor axis. So you can write an equation for each one, with the origin at the intersection of the axes:

Left side:
x2/652 + y2/402 = 1

Right side:
x2/1002 + y2/402 = 1

The length is just 2*y. So rearrange for y:
If the line is on the left side:
length = 2 * sqrt( 402(1-x2/652) )
Where x is the distance from the intersection of the axes.
 
Out of sight. Thanks!:biggrin:
 

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