Legendre's differential equation

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Discussion Overview

The discussion centers on Legendre's differential equation, specifically its general solution and the nature of its solutions. Participants explore the properties of the equation, including its singular points and the relationship between Legendre polynomials and functions of the second kind. The scope includes mathematical reasoning and technical explanations related to ordinary differential equations (ODEs).

Discussion Character

  • Technical explanation
  • Mathematical reasoning

Main Points Raised

  • One participant presents the Legendre differential equation and its general solution, noting that it includes Legendre polynomials and functions of the second kind.
  • Another participant confirms that for each n, the equation has two linearly independent solutions, with P0(x)=1 being one of them for n=0.
  • It is mentioned that the equation has singular points at ±1, with one solution being finite for all finite x and the other being singular at those points.
  • Some participants discuss the derivation of solutions and the use of LaTeX for mathematical expressions.

Areas of Agreement / Disagreement

Participants generally agree on the nature of the solutions to Legendre's differential equation and the existence of singular points. However, there is no explicit consensus on the details of the derivation or the implications of the solutions presented.

Contextual Notes

There are unresolved aspects regarding the derivation steps and the implications of the singular points, as well as the completeness of the solutions discussed.

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the question is in the jpg file
 

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Legendre's differential equation
\\

\[(1-x^2)y''-2xy'+n(n+1)y=0 \]

\\

The general solution is

\[y=c_1P_n(x)+c_2Q_n(x) \] where $n=1,2,3,...$

\\

$P_n(x)$ is Legendre polynomials and $Q_n(x)$ is Legendre functions of the second kind
\\ \\
From the general solutions of Legendre polynomials, we know that
\[
P_0(x)=1
\]
However, we can also find the same solution by letting n=0 for the legendre's differential equation

\[(1-x^2)y''-2xy'+=0 \]

\[\frac{\,dy'}{\,dx}=\frac{2xy'}{1-x^2}\]

\[\int \frac{\,dy'}{y'}=\int \frac{2x}{1-x^2}\]

\[\ln y' = -\ln |1-x^2| + D \]

\[y'=\frac{B}{1-x^2}\]

Find y is pretty straightforward

\[y=A\ln \left[B \left(\frac{1+x}{1-x}\right)\right]\]
 
The Legendre differential equation is a second-order ODE, so it has two linearly independent solutions for each n. P0(x)=1 is one of the two solutions for n=0. You found the other solution.

The Legendre differential equation has singular points at [itex]\pm 1[/itex]. For a given n, one of the two solutions will be finite for all finite x, while the other solution will be singular at the singular points [itex]\pm 1[/itex]. The first set of solutions (finite for all finite x) are the Legendre polynomials. The second set are the Legendre functions of the second kind.
 
BTW, you obviously know LaTeX. This forum supports LaTeX. The start of your post converted to vB LaTeX:

Legendre's differential equation

[tex](1-x^2)y''-2xy'+n(n+1)y=0[/tex]

The general solution is

[tex]y=c_1P_n(x)+c_2Q_n(x)\ \text{where}\ n=1,2,3,\cdots[/tex]
 
The Legendre differential equation is a second-order ODE, so it has two linearly independent solutions for each n. P0(x)=1 is one of the two solutions for n=0. You found the other solution.

The Legendre differential equation has singular points at . For a given n, one of the two solutions will be finite for all finite x, while the other solution will be singular at the singular points . The first set of solutions (finite for all finite x) are the Legendre polynomials. The second set are the Legendre functions of the second kind


BTW, you obviously know LaTeX. This forum supports LaTeX. The start of your post converted to vB LaTeX:

Legendre's differential equation


The general solution is
y = cp(x)1 + dq(x)2 as n= 1,2,3..

i thik he give a good solution ..,
 

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