1. The problem statement, all variables and given/known data A ladder 4.92 m long leans against a wall inside a spaceship. From the point of view of a person on the ship, the base of the ladder is 3.13 m from the wall, and the top of the ladder is 4.00 m above the floor. The spaceship moves past the Earth with a speed of 0.919c in a direction parallel to the floor of the ship. Calculate the angle the ladder makes with the floor, as seen by an observer on Earth. 2. Relevant equations L=L0*sqrt(1-(v^2/c^2)) inverse tan= height above floor/L0 to find angle 3. The attempt at a solution I don't know what I'm doing wrong here. I use L=L0*sqrt(1- v^2/c^2) and find LO (the proper length). Then I use inverse tan= height above floor/L0 to get the angle. But it isn't right. First off, my L0 is longer than that hypotenuse of the triangle, so that's just wrong... What am I doing wrong here?