- #1

- 26

- 0

## Homework Statement

A ladder 4.92 m long leans against a wall inside a spaceship. From the point of view of a person on the ship, the base of the ladder is 3.13 m from the wall, and the top of the ladder is 4.00 m above the floor. The spaceship moves past the Earth with a speed of 0.919c in a direction parallel to the floor of the ship. Calculate the angle the ladder makes with the floor, as seen by an observer on Earth.

## Homework Equations

L=L0*sqrt(1-(v^2/c^2))

inverse tan= height above floor/L0 to find angle

## The Attempt at a Solution

I don't know what I'm doing wrong here. I use L=L0*sqrt(1-

v^2/c^2) and find LO (the proper length). Then I use

inverse tan= height above floor/L0 to get the angle. But it

isn't right. First off, my L0 is longer than that

hypotenuse of the triangle, so that's just wrong...

What am I doing wrong here?