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Length Contraction and a Relativistic Angle

  • Thread starter Cheezay
  • Start date
  • #1
26
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Homework Statement


A ladder 4.92 m long leans against a wall inside a spaceship. From the point of view of a person on the ship, the base of the ladder is 3.13 m from the wall, and the top of the ladder is 4.00 m above the floor. The spaceship moves past the Earth with a speed of 0.919c in a direction parallel to the floor of the ship. Calculate the angle the ladder makes with the floor, as seen by an observer on Earth.



Homework Equations


L=L0*sqrt(1-(v^2/c^2))

inverse tan= height above floor/L0 to find angle


The Attempt at a Solution


I don't know what I'm doing wrong here. I use L=L0*sqrt(1-
v^2/c^2) and find LO (the proper length). Then I use
inverse tan= height above floor/L0 to get the angle. But it
isn't right. First off, my L0 is longer than that
hypotenuse of the triangle, so that's just wrong...
What am I doing wrong here?
 

Answers and Replies

  • #2
181
0
L0 is the distance as measured in the spaceship (given)
L is the distance as observed from earth.
 
  • #3
26
0
I see. Lo will be the distance from the wall to the base of the ladder.
 
Last edited:

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