Length Contraction/Relativistic mass question

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SUMMARY

The discussion centers on calculating the speed of spaceship B and the relativistic mass of spaceship A as observed from Earth. Using the Lorentz factor (γ), it was determined that the speed of spaceship B is 0.934c, where c is the speed of light. The relativistic mass of spaceship A, initially 15000 kg, is calculated to be 21000 kg when accounting for its velocity of 0.70c. The calculations utilize the equations γ = 1/√(1 - v²/c²) and mm = ms/√(1 - v²/c²).

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  • Understanding of the Lorentz factor (γ) in special relativity
  • Knowledge of proper length and proper mass concepts
  • Familiarity with relativistic mass calculations
  • Basic understanding of velocity as a fraction of the speed of light (c)
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  • Study the derivation and applications of the Lorentz factor (γ)
  • Learn about relativistic effects on length contraction and time dilation
  • Explore the implications of relativistic mass in high-speed physics
  • Investigate the differences between rest mass and relativistic mass
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Students and educators in physics, particularly those focusing on special relativity, as well as anyone interested in understanding the effects of high-speed travel on mass and length.

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Homework Statement



The proper length of spaceship A is 60.0m and the proper length of spaceship B is 120.0m. The proper mass of spaceship A is 15000 kg. An observer on Earth watches the two spaceships fly past at a constant speed and determines that they have the same length. If the speed of the slower ship is 0.70c, find:

a-The speed of spaceship B, relative to an observer on earth

b- The mass of spaceship A, relative to an observer on earth

2. Homework Equations


γ = 1/ √1- v2 / c2

mm = ms / √ 1- v2 / c2

The Attempt at a Solution

a)

Use the Lorentz factor to determine the velocity of ship B

γ = proper length B/ contracted length A

γ = 120m /42.8m

γ = 2.8γ = 1/ √1- v2 / c2rearrange to solve for v.
γ2 = 1/ √1- v2 / c2

1 - v2 / c2 = 1/γ2

v2 / c2 = 1 - 1/γ2

v/c = √1- 1/2.82

v/c = √1- 1/7.84

v = 0.934

The speed of spaceship B, relative to an observer on Earth will be 0.934c.

b) The mass of spaceship A, relative to an observer on earth. 3mk

mm = ms / √ 1- v2 / c2

mm = 15000kg / √1- 0.70c2 / c2

mm = 15000kg / √1- 0.49

mm =2100.4
https://www.physicsforums.com/file://localhost/Users/jefferyhewitt/Library/Group%20Containers/UBF8T346G9.Office/msoclip1/01/clip_image016.pngThe mass of spaceship A, relative to an observer on Earth, is 2100kg.The main part I am unsure of is question a, I hadn't specifically been taught about the Lorentz Factor, but this is all I could find that seemed to be able to determine the answer. As such I am not sure if I applied it correctly. If someone could give a few pointers that would be great.
 
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The answer to (a) is correct. The Lorentz factor ##\gamma=\frac{1}{\sqrt{1-v^2/c^2}}## is greater than 1 when ##v\neq 0##. The contracted length would be ##L=L_0/\gamma##. Your answer to (b) is missing a zero, probably a typo. The mass of the moving rocket must be greater than its rest mass, not less.
 
kuruman said:
The answer to (a) is correct. The Lorentz factor ##\gamma=\frac{1}{\sqrt{1-v^2/c^2}}## is greater than 1 when ##v\neq 0##. The contracted length would be ##L=L_0/\gamma##. Your answer to (b) is missing a zero, probably a typo. The mass of the moving rocket must be greater than its rest mass, not less.
Yes it is missing a 0, thanks for the explanation
 

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