Length of acceleration for a rock fragment escaping Mars

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SUMMARY

The discussion centers on the physics of rock fragments escaping Mars, specifically the acceleration required to reach the planet's escape velocity of 5.0 km/s over a distance of 4.0 meters. The calculated acceleration is 3.13e6 m/s². The confusion arises in determining the duration of this acceleration, with the initial incorrect assumption being 0.0016 seconds. The correct approach involves using the formula for distance under constant acceleration to derive the time variable in relation to acceleration.

PREREQUISITES
  • Understanding of basic physics concepts such as acceleration and velocity.
  • Familiarity with kinematic equations, particularly those involving constant acceleration.
  • Knowledge of unit conversions, especially between meters and kilometers.
  • Ability to solve algebraic equations to find unknown variables.
NEXT STEPS
  • Review kinematic equations for motion under constant acceleration.
  • Study unit conversion techniques, particularly for speed and distance.
  • Explore the implications of escape velocity in planetary science.
  • Investigate the history and significance of Martian meteorite ALH 84001.
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Students and educators in physics, planetary scientists, and anyone interested in astrobiology and the potential for life transfer between planets.

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Homework Statement



It has been suggested, and not facetiously, that life might have originated on Mars and been carried to Earth when a meteor hit Mars and blasted pieces of rock (perhaps containing primitive life) free of the surface. Astronomers know that many Martian rocks have come to Earth this way. (For information on one of these, search the Internet for “ALH 84001”.) One objection to this idea is that microbes would have to undergo an enormous, lethal acceleration during the impact. Let us investigate how large such an acceleration might be. To escape Mars, rock fragments would have to reach its escape velocity of 5.0 km/s , and this would most likely happen over a distance of about 4.0m during the impact.

a) What would the acceleration in such a rock fragment be?
I got this part! 3.13e6 m/s^2

b) How long would this acceleration last?
This the part I am confused about. I thought it was 0.0016 s but that is incorrect. Any help would be appreciated!
 
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Let the acceleration, in kilometers per second, of the object after after the impact be "a". Then the speed, t seconds after initial impact, is at and the distance moved is (a/2)t^2. We know that the distance is 4m= .004 km so we can solve (a/2)t^2= 4 for t in terms of a. Put that into at= 5 km/s to get an equation for a.
 
Thanks for the reply! I figured out that I actually had the right answer I was just confusing the units.
 
how did you find part A?
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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