MHB Let F ={0 , 1 , a , b} be a field with four elements.

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Let F ={0 , 1 , a , b} be a field with four elements. What is a + b^2 and a^2 + b^2.

Apparently, the answers are b and 1, respectively. How do we come to that conclusion?
 
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rayne said:
Let F ={0 , 1 , a , b} be a field with four elements. What is a + b^2 and a^2 + b^2.

Apparently, the answers are b and 1, respectively. How do we come to that conclusion?

Hi rayne!

Can you set up a multiplication table?
And an addition table?
 
Btw, I do not believe that a + b^2 = b.
There seems to be a mistake in the problem statement.
 
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Hello! In one book I saw that function ##V## of 3 variables ##V_x, V_y, V_z## (vector field in 3D) can be decomposed in a Taylor series without higher-order terms (partial derivative of second power and higher) at point ##(0,0,0)## such way: I think so: higher-order terms can be neglected because partial derivative of second power and higher are equal to 0. Is this true? And how to define vector field correctly for this case? (In the book I found nothing and my attempt was wrong...

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