Let F and y both be continuous for simplicity. Knowing that:(adsbygoogle = window.adsbygoogle || []).push({});

[tex] \int_0^x F'(t)y^2(t) dt = F(x) \quad \forall x \geq 0 [/tex]

can you say that the function [tex] y[/tex] is bounded? Why? I know that [tex] \int_0^x F'(t) dt = F(x) [/tex] but I can't find a suitable inequality to prove rigorously that y is bounded.

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# Let F and y both be continuous for simplicity. Knowing that:[tex]

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