L'hopital's Rule for solving limit problem

[kmeado07]

The question is:
Evaluate the following limit: lim(as x tends to 1) of [(x-1)^3]/(logx)

I tried using L'hopital's Rule, so i differentiated the top and bottom of the eqn and i got 3x(x-1)^2, then as x tends to 1 this would tend to 0.

I don't think this is correct though, and was wondering if anyone could give me some guide lines to maybe another rule to use to find the limit.

Thanks.

 

[Pere Callahan]

I don't think this is correct though, and was wondering if anyone could give me some guide lines to maybe another rule to use to find the limit.

Why would you think so? It's perfectly correct, well done.

 

[kmeado07]

But to use l'hopital's rule, don't you need the limit, x, tending to zero?

 

[Pere Callahan]

No, you only need both the numerator and the denumerator tend to zero (or infinity) as x approaches some number a, for example one.