Ligands and lowering reduction potential

Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
2 replies · 4K views
Chickenpoxpie
Messages
7
Reaction score
0
Hi I have a question I was wondering if y'all could clear up. Let's say I have two metal cations, Iron (III) and Manganese (II). Will binding them to an anionic ligand lower their reduction potentials (making each a better redundant) and if so why?

Is it because the anionic charge of the ligand stabilizes the positive charge of the metals?

What if the ligand binds with a high coordination number (say 5 or 6). Will that further reduce the reduction potential because now the entire complex has a negative charge and is better able to donate electrons (ie good reluctant)?
 
Chemistry news on Phys.org
Basically it is about the concentration of the free metal. You can safely assume what is happening is that it is free metal that reacts, and ligands just change its concentration. Once you know the concentration, it is just a matter of applying Nernst equation.
 
Chickenpoxpie said:
Hi I have a question I was wondering if y'all could clear up. Let's say I have two metal cations, Iron (III) and Manganese (II). Will binding them to an anionic ligand lower their reduction potentials (making each a better redundant) and if so why?

Is it because the anionic charge of the ligand stabilizes the positive charge of the metals?

What if the ligand binds with a high coordination number (say 5 or 6). Will that further reduce the reduction potential because now the entire complex has a negative charge and is better able to donate electrons (ie good reluctant)?

Yes, that's exactly how it works. Read up on Cytochrome p450 and you will see this effect in action.