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Lim as x->a f(x) = L PROOF using epsilon and delta

  1. Oct 10, 2010 #1
    Suppose limx->a f(x) = L does NOT equal 0.

    Prove that there exists a (delta) d > 0 such that 0<|x-a|<d

    which implies f(x) does NOT equal 0.


    Does Anybody Know the Proof For This?
     
  2. jcsd
  3. Oct 10, 2010 #2

    mathman

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    Science Advisor

    Your statement is incomplete.
     
  4. Oct 10, 2010 #3
    Make epsilon less = |L|.
     
    Last edited: Oct 10, 2010
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