Lim as x->a f(x) = L PROOF using epsilon and delta

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    Delta Epsilon Proof
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finishimx7
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Suppose limx->a f(x) = L does NOT equal 0.

Prove that there exists a (delta) d > 0 such that 0<|x-a|<d

which implies f(x) does NOT equal 0.


Does Anybody Know the Proof For This?
 
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Make epsilon less = |L|.
 
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