Lim as x->a f(x) = L PROOF using epsilon and delta

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SUMMARY

The discussion centers on proving the limit statement limx→a f(x) = L, where L does not equal 0. The proof requires establishing the existence of a delta (δ) greater than 0 such that 0 < |x - a| < δ implies f(x) does not equal 0. A key suggestion is to set epsilon (ε) less than |L| to facilitate the proof. This approach ensures that the function f(x) remains bounded away from zero as x approaches a.

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finishimx7
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Suppose limx->a f(x) = L does NOT equal 0.

Prove that there exists a (delta) d > 0 such that 0<|x-a|<d

which implies f(x) does NOT equal 0.


Does Anybody Know the Proof For This?
 
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Your statement is incomplete.
 
Make epsilon less = |L|.
 
Last edited:

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