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Limit Comparison Test for series

  1. Apr 3, 2008 #1
    I have been given the series
    sum 1/sqrt(3n-2) from n=1 to infinity

    I am supposed to use the limit comparison test, and the comparison series my book suggests is sum 1/sqrt n from n=1 to infinity, which I know is a divergent p series

    However, when I take the limit of one divided by the other I come up with 0.

    lim n -> infinity for (sqrt n)/(sqrt 3n-2) = 0

    What am I doing wrong?
  2. jcsd
  3. Apr 4, 2008 #2
    Nevermind, I figured it out.

    This Limit Comparison test shows that the series diverges because the limit is 1/sqrt3.
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