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Limit Comparison Test for series

  • Thread starter bcjochim07
  • Start date
  • #1
374
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I have been given the series
sum 1/sqrt(3n-2) from n=1 to infinity

I am supposed to use the limit comparison test, and the comparison series my book suggests is sum 1/sqrt n from n=1 to infinity, which I know is a divergent p series

However, when I take the limit of one divided by the other I come up with 0.

lim n -> infinity for (sqrt n)/(sqrt 3n-2) = 0

What am I doing wrong?
 

Answers and Replies

  • #2
374
0
Nevermind, I figured it out.

This Limit Comparison test shows that the series diverges because the limit is 1/sqrt3.
 

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