# Homework Help: Limit Comparison Test for series

1. Apr 3, 2008

### bcjochim07

I have been given the series
sum 1/sqrt(3n-2) from n=1 to infinity

I am supposed to use the limit comparison test, and the comparison series my book suggests is sum 1/sqrt n from n=1 to infinity, which I know is a divergent p series

However, when I take the limit of one divided by the other I come up with 0.

lim n -> infinity for (sqrt n)/(sqrt 3n-2) = 0

What am I doing wrong?

2. Apr 4, 2008

### bcjochim07

Nevermind, I figured it out.

This Limit Comparison test shows that the series diverges because the limit is 1/sqrt3.