Limit Evaluation: (x^4+y^4)/((x^2+y^2)^(3/2)) as (x,y) -> (0,0)

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The limit of the expression (x^4+y^4)/((x^2+y^2)^(3/2)) as (x,y) approaches (0,0) is definitively 0. The discussion highlights that there is no need to abbreviate the equation, as analyzing the radial dependence and confirming the absence of singularities in angular dependence suffices for the evaluation. This conclusion is supported by the participants' agreement on the limit's value.

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Evaluate the liit of (x^4+y^4)/((x^2+y^2)^(3/2)) when (x,y) approaches (0,0)

I'm trying to replace x and y with rcost and ycost, but it seems too complex. How can I abbreviate the equation?
...

I solved it myself...The limit is 0.
 
Last edited:
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No need to abbreviate, just analyse the r dependence,
and check that the angular dependence is a has no singularity.

And indeed you are right: 0 is the limit.
 

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