I have to prove from the definiton of the limit of a function that the limit of f(x) as x tends to 2 equlas 3, given that;(adsbygoogle = window.adsbygoogle || []).push({});

f(x)=(2x-1)

I know that I have to find an epsilon such that |f(x)-l| [tex]\leq[/tex] [tex]\epsilon[/tex] and delta such that 0 [tex]\leq[/tex] |x-a| [tex]\leq[/tex] [tex]\delta[/tex]

Nowing putting in the conditions for this f(x);

|2x-4| [tex]\leq[/tex] [tex]\epsilon[/tex] and 0 [tex]\leq[/tex] |x-2| [tex]\leq[/tex] [tex]\delta[/tex]

But I don't where to go from here. Any help would be great!

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# Limit Of A Function From Definition

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