Limit of a Geometric Sequence: How to Evaluate?

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SUMMARY

The limit of the geometric sequence defined by the expression $$\lim_{{n}\to{\infty}} {(\frac{2}{3})}^{n}$$ evaluates to 0. This conclusion is reached by recognizing that as n approaches infinity, the term $$\left(\frac{2}{3}\right)^n$$ can be rewritten using the exponential function as $$e^{n\ln(2/3)}$$. Since $$\ln(2/3)$$ is negative, the limit simplifies to $$\lim_{n\to\infty} e^{-n\ln(3/2)}$$, which confirms that the limit approaches 0.

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I have this limit:

$$\lim_{{n}\to{\infty}} {(\frac{2}{3})}^{n}$$

I know the answer is 0 but how can I evaluate this?
 
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Can you agree that $\lim_{n\to\infty}\dfrac{1}{e^n}=0$, without calculation?

If so,

$$\lim_{n\to\infty}\left(\dfrac23\right)^n=\lim_{n\to\infty}e^{n\ln(2/3)}=\lim_{n\to\infty}e^{-n\ln(3/2)}$$

$$=\lim_{n\to\infty}\left(\dfrac{1}{e^n}\right)^{\ln(3/2)}=0^{\ln(3/2)}=0$$
 

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