Evaluate Limit: $$\lim_{x\to\infty} (-1)^nn^3 + 2^{-n}$$

  • Context:
  • Thread starter Thread starter tmt1
  • Start date Start date
  • Tags Tags
    Limit
Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
2 replies · 2K views
tmt1
Messages
230
Reaction score
0
I have this limit:

$$\lim_{{x}\to{\infty}} {(-1)}^{n}{n}^{3} + {2}^{-n}$$

and I'm unsure how to evaluate it or how to apply L'hopital's rule to this limit.
 
Physics news on Phys.org
tmt said:
I have this limit: $$\lim_{n\to\infty} (-1)^n\,n^3 + 2^{-n}$$

and I'm unsure how to evaluate it or how to apply L'hopital's rule to this limit.
L'Hopital's rule doesn't apply here.

We see that: [tex]\lim_{n\to\infty}2^{-n}\:=\:0[/tex]

But the first part is an alternating sequence of cubes:
. . [tex]-1 + 8 - 27 + 64 - 125 + \cdots[/tex] which diverges.

 
It's a limit, not a series - the limit does not exist.