Limit of exp(z) (complex number)

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Homework Help Overview

The discussion revolves around finding the limit of the exponential function as a complex variable approaches infinity. Participants are exploring the behavior of the function exp(z) where z is a complex number.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss substituting z with iy, where y is real, and consider the implications of this substitution as y approaches infinity. There is a focus on the oscillatory nature of the exponential function when expressed in terms of trigonometric functions.

Discussion Status

Some participants have raised questions about the oscillatory behavior of the function and its implications for the limit. There is an acknowledgment of different paths leading to varying limits based on the approach taken towards infinity, indicating a productive exploration of the topic.

Contextual Notes

Participants note that depending on the path taken in the complex plane, such as approaching along the real axis versus the imaginary axis, the limits can yield different results, which complicates the determination of a single limit as z approaches infinity.

rmcclurk
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Homework Statement



Find limit as z->infinity of exp(z) where z is complex

Homework Equations



See above

The Attempt at a Solution



The solution should be that the limit does not exist, but I don't know why. Any explanations?
 
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Put z=iy, where y is real. Now let y->infinity.
 
Is it because e^iy = r(cos(y)+i*sin(y)) and that equation simply oscillates and never goes to infinity no matter how large y gets?
 
rmcclurk said:
Is it because e^iy = r(cos(y)+i*sin(y)) and that equation simply oscillates and never goes to infinity no matter how large y gets?

Right, if you put r=1. Or consider z=x and z=(-x) for x real and let x->+infinity. One limit is infinity, and the other is zero. There is no definite single limit as z->infinity. Consider definite cases of z->infinity to get a feeling for what's going on.
 
Thanks a lot got it figured out
 

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