Limit of Sequence: Convergent, Limit = 1

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SUMMARY

The sequence defined by \(\left(\frac{4^n}{n}\right)^{\frac{1}{n}}\) converges to a limit of 1 as \(n\) approaches infinity. This conclusion is reached by applying the limit property \(\lim_{n \to \infty} n^{\frac{1}{n}} = 1\) and recognizing that the growth of \(4^n\) in the numerator outpaces the linear growth of \(n\) in the denominator. The exponent approaches 0, confirming that the overall expression converges to 1.

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Homework Statement



Determine if the following sequence in convergent or divergent, and state the limit if it converges.

((4^n)/n)^(1/n) or "The nth root of '4 to the n' over 'n'"

Homework Equations



lim ___(n)^(1/n) = 1
n->inf

The Attempt at a Solution



I had this question on a quiz earlier, but wasn't too sure about my answer. As n approaches infinity, the exponent on the very outside approaches 0. So naturally I thought that anything to the 0 is 1. However, thinking back on it, I think the inside gets larger faster than the outside exponent gets smaller. Thanks for any help, I don't want to wait until Monday!
 
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Try using the property

[tex]\left(\frac{a}{b}\right)^n = \frac{a^n}{b^n}[/tex]

and then the limit you noted.
 

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