- #1

Sirsh

- 267

- 10

## Homework Statement

The position vector of a particle is given in the terms of t, by,

**s**= (e

^{-t}+3*cos(2t)

**i**+2t

**j**+(e

^{-t}+3*sin(2t)

**k**)

Find the limiting value of speed when t approaches positive infinity. The answer says "s = ..."

## The Attempt at a Solution

I have evaluated the limits of all the components of this vector function individually:

e

^{-t}= 0

3*cos(2t) = -3 to 3

2t = positive infinity

3*sin(2t) = -3 to 3.

I know that the magnitude of the velocity vector is equal to the speed of the particle, so I'm not sure if i should have done the limits on the velocity vector that i found by differentiating the position vector? but the answer is in the form of "s = ..."

Any help would be appreciated, Thanks!