Limiting x^2/(x-1) as x Approaches 1 from the Left

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SUMMARY

The limit of the function x^2/(x-1) as x approaches 1 from the left is negative infinity. This conclusion is derived from the fact that as x approaches 1 from the left, the numerator x^2 approaches 1, while the denominator (x-1) approaches 0 from the negative side, resulting in the overall expression tending towards negative infinity. The algebraic manipulation shows that the limit can be expressed as the sum of two terms, where the first term approaches 2 and the second term diverges negatively.

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Homework Statement


Find the limit of x^2/(x-1) as x goes to 1 from the left.




Homework Equations





The Attempt at a Solution


It doesn't seem I can factor anything, but could I assume that since the numerator is a constant and the denomination is going to be negative because it's <1 then it's going to negative infinity? Is there anyway to show this algebraically? Thanks.
 
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DrummingAtom said:

Homework Statement


Find the limit of x^2/(x-1) as x goes to 1 from the left.

Homework Equations


The Attempt at a Solution


It doesn't seem I can factor anything, but could I assume that since the numerator is a constant and the denomination is going to be negative because it's <1 then it's going to negative infinity? Is there anyway to show this algebraically? Thanks.

You are correct.

\frac{x^2}{1-x} = \frac{x^2 -1}{1-x} + \frac{1}{1-x}

The limit as x-> 1^{-} of \frac{x^2 -1}{1-x} is 2.
This
\frac{1}{1-x} one does not exist.
 

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