Limiting x^2/(x-1) as x Approaches 1 from the Left

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The limit of x^2/(x-1) as x approaches 1 from the left is being analyzed. As x approaches 1, the numerator approaches 1, while the denominator approaches 0 from the negative side, leading to the conclusion that the limit approaches negative infinity. A breakdown of the expression shows that the limit can be evaluated by separating it into two parts, where one part approaches 2 and the other diverges negatively. Therefore, the overall limit is confirmed to be negative infinity. This demonstrates the behavior of the function near the point of interest.
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Homework Statement


Find the limit of x^2/(x-1) as x goes to 1 from the left.




Homework Equations





The Attempt at a Solution


It doesn't seem I can factor anything, but could I assume that since the numerator is a constant and the denomination is going to be negative because it's <1 then it's going to negative infinity? Is there anyway to show this algebraically? Thanks.
 
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DrummingAtom said:

Homework Statement


Find the limit of x^2/(x-1) as x goes to 1 from the left.

Homework Equations


The Attempt at a Solution


It doesn't seem I can factor anything, but could I assume that since the numerator is a constant and the denomination is going to be negative because it's <1 then it's going to negative infinity? Is there anyway to show this algebraically? Thanks.

You are correct.

\frac{x^2}{1-x} = \frac{x^2 -1}{1-x} + \frac{1}{1-x}

The limit as x-> 1^{-} of \frac{x^2 -1}{1-x} is 2.
This
\frac{1}{1-x} one does not exist.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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