Graduate Limits and Supremum: Is It True?

  • Thread starter Thread starter Mathvsphysics
  • Start date Start date
  • Tags Tags
    Limits Supremum
Click For Summary
The discussion centers on the convergence of a sequence ##a_n## in norm to a limit ##a## and the behavior of the supremum of the inner product with respect to a set ##S##. It questions whether the supremum ##\sup_{s\in S} <a,s> < +\infty## holds true given that ##\sup_{s\in S} <a_n,s> < +\infty## for all ##n \ge 0##. Participants suggest that if there exists a constant ##M \in R## such that ##\sup <a_n,s> < M## and an epsilon condition is satisfied, it implies a boundedness in the limit. The conversation emphasizes the need for clear definitions and conditions to establish the validity of the supremum statement. Overall, the thread explores the implications of convergence and boundedness in the context of functional analysis.
Mathvsphysics
Messages
1
Reaction score
1
We have ##a_n## converges in norm to ##a## and a set ##S## such that for all ##n\ge 0##
$$\sup_{s\in S} <a_n,s><+\infty .$$ Is it true that ##\sup_{s\in S} <a,s><+\infty##
 
Last edited by a moderator:
Physics news on Phys.org
You need to use two hashes (or two dollars) for Latex delimiters.
 
Is this a homework-type of problem? There is a format for those and you must show work before we can give hints.
Suppose ##M \in R## is such that ##sup<a_n,s> \lt M##. Also, suppose ##\epsilon \gt 0## and ##m\in N## are such that ##<a_n,a> \lt \epsilon## ##\forall n\gt m##. What can you say then?
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
2
Views
1K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 44 ·
2
Replies
44
Views
7K
  • · Replies 13 ·
Replies
13
Views
3K