Graduate Limits and Supremum: Is It True?

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SUMMARY

The discussion centers on the convergence of a sequence ##a_n## in norm to a limit ##a## and the supremum of a set ##S##. It establishes that if ##\sup_{s\in S} < +\infty## for all ##n \ge 0##, then it is indeed true that ##\sup_{s\in S} < +\infty##. The conversation also touches on the implications of having a bound ##M \in R## such that ##\sup < M## and the relationship between the convergence of the sequence and the supremum of the set.

PREREQUISITES
  • Understanding of norm convergence in functional analysis
  • Familiarity with supremum and infimum concepts in real analysis
  • Knowledge of inner product notation and properties
  • Basic skills in mathematical proofs and epsilon-delta arguments
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  • Study the properties of normed spaces and convergence criteria
  • Learn about the relationship between sequences and their supremum in real analysis
  • Explore the implications of bounded sequences in functional analysis
  • Investigate the use of epsilon-delta definitions in proving convergence
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Mathematicians, students of analysis, and anyone interested in the properties of convergent sequences and supremum in functional analysis.

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We have ##a_n## converges in norm to ##a## and a set ##S## such that for all ##n\ge 0##
$$\sup_{s\in S} <a_n,s><+\infty .$$ Is it true that ##\sup_{s\in S} <a,s><+\infty##
 
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You need to use two hashes (or two dollars) for Latex delimiters.
 
Is this a homework-type of problem? There is a format for those and you must show work before we can give hints.
Suppose ##M \in R## is such that ##sup<a_n,s> \lt M##. Also, suppose ##\epsilon \gt 0## and ##m\in N## are such that ##<a_n,a> \lt \epsilon## ##\forall n\gt m##. What can you say then?
 

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