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**do**know, in my head what the graph looks like so I know that there is a horizontal asymptote is y=0. I just have to show my work, thats where I'm stuck.

Here is the problem:

lim(x->infinity)(2e^x)

My attempt:

lim(x->infinity)(2e^x) = lim(x->infinity)(2/e^-x)

=lim(x->infinity)(2/e^-infinity)

=lim(x->infinity)(2/0)

=0 Therefore: y=0

I'm not sure if I'm doing the problem the right way. If I did somehow get it right, can someone please give me a brief description on the proper method?

Thanks In Advance.