Line of infinite charge and a gaussian sphere

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SUMMARY

The discussion focuses on applying Gauss' Law to a spherical Gaussian surface centered on an infinite line of charge. Participants confirm that while calculating the electric flux through the sphere may seem tedious, it effectively demonstrates the power of symmetry in Gauss' Law. The key steps involve determining the electric field E(r) at a point defined by the polar angle θ and integrating over the spherical surface. This approach validates the principles of electrostatics and reinforces the understanding of electric fields around charged objects.

PREREQUISITES
  • Understanding of Gauss' Law
  • Familiarity with electric fields and flux concepts
  • Knowledge of spherical coordinates
  • Basic calculus for integration
NEXT STEPS
  • Study the derivation of electric fields from charge distributions using Gauss' Law
  • Learn about the application of symmetry in electrostatics
  • Explore the concept of electric flux in different geometries
  • Practice integration techniques in spherical coordinates
USEFUL FOR

Physics students, educators, and anyone interested in electrostatics and the application of Gauss' Law in complex charge distributions.

stunner5000pt
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Construct a spherical gaussian surface centered on an infinite line of charge. Calculate the flux through the sphere and thereby show that it satisfies gauss law.

I know how i can do it for a cylinder, but a sphere?

I know that the ends of the wire (one diameter) wil have zero flux at it's ends

but wouldn't i have to integrate over a big hemispherical surface and then multiply by two but ... wouldn't it be tedious?
 
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stunner5000pt said:
but wouldn't i have to integrate over a big hemispherical surface and then multiply by two but ... wouldn't it be tedious?

Yes, but that's probably the reason they're asking you to do it. It shows the power of symmetry in applying Gauss' Law.
 
It's not hard. You know what E(r) is. Take a point at polar angle \theta and find E(r).n in terms of \theta. Integrate over the sphere.
 

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