Linear algebra and seats in a van

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SUMMARY

The discussion centers on a linear algebra problem involving two vans with a total seating capacity of 69. The smaller van has 9 fewer seats than the larger van and makes two trips, while the larger van makes one trip. The equations derived are Y = X + 9 and 69 = X + 2X + 9, leading to the conclusion that the smaller van has 30 seats. Consequently, the larger van has 39 seats, as calculated by Y = 30 + 9.

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yuuri14
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Homework Statement




A Company use two vans from 7-9am. ONE van has 9 more seat than the other. The smaller van makes two trips, and the larger van make 1 trip?
The maximum seats of both vans that was given would be 69.
Let x be the seats of small van and y be the seat of the larger van.
How many seats does the LARGER VAN have?

Homework Equations


USE LINEAR


The Attempt at a Solution


Y=X+9
69=X+x+9
-9 -9
60=2X
2 2
X=30.....
THAT THE ANSWER BUT BACK TO THE QUESTION (How many seats does the LARGER VAN have? and the fact that the smaller van takes two trips) what's after that is it 30 x 2= 60 because x is the smaller van, two trips then subtract to total number of both 69-60=9
y=9
 
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Your equations are faulty. The small van makes TWO trips, while the big van only ONE. The THREE trips counted together can transport 69 people. Hope this makes it clearer.

Cheers
 

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