Mdhiggenz Messages 324 Reaction score 1 Thread starter Apr 6, 2013 #1 Homework Statement Hello, I took my quiz today, and had to find a basis for an orthogonal compliment, would it be incorrect to not factor out the alphas and betas? Homework Equations The Attempt at a Solution
Homework Statement Hello, I took my quiz today, and had to find a basis for an orthogonal compliment, would it be incorrect to not factor out the alphas and betas? Homework Equations The Attempt at a Solution
micromass Staff Emeritus Science Advisor Homework Helper Insights Author Messages 22,170 Reaction score 3,335 Apr 6, 2013 #2 I have no idea what you're asking. Please provide more details.
Mdhiggenz Messages 324 Reaction score 1 Apr 6, 2013 #4 With pleasure. Let S be the subspace of R4 spanned by x = (1;2;3;4)T and y = (0;1;0;1)T Find a basis of S orthogonal compliment So I found the correct basis however I did not factor out the alpha's and betas. Since we had free variables.
With pleasure. Let S be the subspace of R4 spanned by x = (1;2;3;4)T and y = (0;1;0;1)T Find a basis of S orthogonal compliment So I found the correct basis however I did not factor out the alpha's and betas. Since we had free variables.
micromass Staff Emeritus Science Advisor Homework Helper Insights Author Messages 22,170 Reaction score 3,335 Apr 6, 2013 #5 I still have no idea what you mean with alpha's and beta's. Can you show me your work or your final solution?
I still have no idea what you mean with alpha's and beta's. Can you show me your work or your final solution?
Mdhiggenz Messages 324 Reaction score 1 Apr 6, 2013 #6 x1+2x2+3x3+4x4=0 x2+x4=0 x3 and x4 are my free variables setting x3=a x4=B We get x2=-B x1-2B+3a+4B=0 x1=-2B-3a basis would be {(-2B-3a)^T,-B^T,a^T,B)}
x1+2x2+3x3+4x4=0 x2+x4=0 x3 and x4 are my free variables setting x3=a x4=B We get x2=-B x1-2B+3a+4B=0 x1=-2B-3a basis would be {(-2B-3a)^T,-B^T,a^T,B)}