Linear Algebra - orthogonal vector fields

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SUMMARY

The discussion centers on proving the relationship between the kernel of the adjoint operator T* and the image of the operator T in finite-dimensional spaces, specifically that Ker(T*) equals the orthogonal complement of Im(T), denoted as [Im(T)]⊥. The user demonstrates the proof by showing that any vector in the kernel of T* is orthogonal to every vector in the image of T, thus establishing the required relationship. The proof is confirmed to be valid, addressing the user's initial doubts regarding its correctness.

PREREQUISITES
  • Understanding of linear transformations and their properties.
  • Familiarity with the concepts of kernel and image of operators.
  • Knowledge of inner product spaces and orthogonality.
  • Basic proficiency in finite-dimensional vector spaces.
NEXT STEPS
  • Study the properties of adjoint operators in linear algebra.
  • Explore the concepts of orthogonal complements in vector spaces.
  • Learn about the implications of the Rank-Nullity Theorem.
  • Investigate applications of linear transformations in functional analysis.
USEFUL FOR

Students and professionals in mathematics, particularly those studying linear algebra, as well as educators seeking to deepen their understanding of operator theory and its applications in finite-dimensional spaces.

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I want to prove that: Ker(T*)=[Im(T)]^\bot
Everything is in finite dimensions.

What I'm trying:
Let v be some vector in ImT, so there is v' so that Tv'=v.
Let u be some vector in KerT*, so T*u=0.

So now:
<u,v>=<u,Tv'>=<T*u,v'>=0 so every vector in ImT is perpendicular to every vector in KerT*.
So Ker(T*)=[Im(T)]^\bot

My intuition tells me that there is something wrong here but I can' put a finger on it.
 
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