Linear combination of linear combinations?

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The discussion centers on the notation [[S]] and its relationship to [S], where [S] represents the span of a subset S in a finite-dimensional vector space V. It clarifies that [[S]] is essentially a linear combination of linear combinations of elements from [S], and confirms that [[S]] equals [S]. The conversation also touches on the equivalence of different definitions of a set E in relation to subsets of V, emphasizing that the [[]] notation is not fundamentally different from the [] notation. Participants suggest using clearer mathematical notation for better understanding. Ultimately, the key point is that [[S]] is defined through repeated application of the linear combination concept.
bonfire09
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When the book says "Members of [] are linear combinations of linear combinations of members of S". basically means the span of the members in subspace S. Since
= {c1s1 +... + cnsn|c1...cnεR and s1...snεS} what does [] mean? does it mean a linear combination of atleast one linear or more linear combinations from ?
 
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Let V be a finite-dimensional vector space. For all subsets S⊂V, is the set of all v in V such that v is equal to a linear combination of members of S. Since that makes a subset of V, the definition applies to as well. So [] is the set of all v in V such that v is equal to a linear combination of members of .

It's possible to prove that if E,F⊂V, the following statements are equivalent (i.e. they're either all true or all false).

(a) E is the set of all v in V such that v is a linear combination of members of F.
(b) E is the intersection of all subspaces that have F as a subset.
(c) E is the smallest subspace that has F as a subset. (This means that if E' is a subspace that has F as a subset, E⊂E').

A set E for which these statements are true is, in your notation, denoted by [F]. If you only look at (a), it's not obvious that []=, but if you look at the other two statements, it is.

Two alternative notations for : span S, ##\bigvee S##.
 
Yeah I forgot to mention []=. But the book states that [] is a linear combination of linear combinations of the members of . Does this let's say set R={c1,1s1+...+cn,1sn,...,c1,m s1+...+cn,m sn} which is the set of all linear combinations of . And [] just means taking a linear combination of those members in R such as
r1(c1,1s1+...+cnsn)+...+rn(c1,m s1+...+c n,m sn) ? Oh s1,...sn. are elements of S and S is a subspace of V
 
bonfire09 said:
Yeah I forgot to mention []=.

I thought that was what you were asking about, not something you already knew.

bonfire09 said:
But the book states that [] is a linear combination of linear combinations of the members of

You mean "of S", right? (Not "of ").

bonfire09 said:
Does this let's say set R={c1,1s1+...+cn,1sn,...,c1,m s1+...+cn,m sn} which is the set of all linear combinations of .

What does that mean? And did you again mean S when you wrote ?

bonfire09 said:
And [] just means taking a linear combination of those members in R such as
r1(c1,1s1+...+cnsn)+...+rn(c1,m s1+...+c n,m sn) ?

I don't understand what you're asking, but the meaning of [] is given by the definition of the [] notation.

Maybe you meant to ask this: If we define R=, does that make []=[R]? The answer is of course yes. The [[]] notation isn't something entirely different from the [] notation. It's just the [] operation done twice.

bonfire09 said:
S is a subspace of V
It doesn't have to be.

I recommend that you start using LaTeX, or at least vBulletin's sup and sub tags. (Like this: E=mc2).
 
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