Linear combination of two solutions of the simplified schroedinger equation

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The discussion centers on the linear combination of solutions to the simplified Schrödinger equation, specifically the equation \(\frac{d^{2}}{dx^{2}}ψ=-\frac{4πm}{h}*[E-U(x)]ψ(x)\). Participants confirm that if ψ1 and ψ2 are solutions for the same potential energy U(x), then the linear combination Aψ1 + Bψ2 is also a valid solution. The proof involves substituting this combination into the differential equation, which validates the assertion. The original poster expresses a desire for a more formal proof but ultimately recognizes that their confirmation serves as proof.

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freddyfish
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This is, when it all comes around, just math. I am asked to prove that if the schroedinger equation looks like:

\frac{d^{2}}{dx^{2}}ψ=-\frac{4πm}{h}*[E-U(x)]ψ(x)

and ψ1 and ψ2 are two separate solutions for the same potential energy U(x), then Aψ1 + Bψ2 is also a solution of the equation.

I am asking this because I think it is obvious that the last solution also satisfies the S.E. if the two terms of it are two individual solutions.

To show that the linear combination is also a solution all you have to do is replace ψ by Aψ1 + Bψ2 in the differential equation, but this feels more like confirming rather than proving. Since I'm pretty new to this quantum mechanic discipline, I would prefer a simple proof, and if there is no simple proof that is more of a proof than a confirmation of the statement, then I have probably already answered the question in the way intended.

Thanks //F
 
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You already have the proof. Your "confirming" stands for proving.
 
Thanks for your answer. I came here now to actually post that I found it to be the desired solution :p

I was not too satisfied finding out that I already had come up with the answer according to the solutions manual, since I prefer to start at the opposite end and prove the statement without using the fact that I know where I should end up after carrying through the proving process.

The Schroedinger equation can't be proven, I know that. But the problem I was asked to solve was just about the mathematical representation of the S.E. so I gave it a shot B-)
 

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