Linear Differential Equations in Kinematics

  • Context: Graduate 
  • Thread starter Thread starter P3X-018
  • Start date Start date
  • Tags Tags
    Kinematics
Click For Summary

Discussion Overview

The discussion revolves around solving linear differential equations in the context of kinematics, particularly focusing on equations that describe motion with air resistance. Participants explore methods for integrating these equations, share their approaches, and debate the correct application of mathematical techniques.

Discussion Character

  • Technical explanation
  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • One participant presents the equations \(\ddot{x}(t)+\alpha \dot{x}(t)^2=0\) and \(\ddot{y}(t)+\alpha\dot{y}(t)^2=-g\) and seeks help with the integration involved in solving them.
  • Another participant points out that the equations are not linear and suggests rewriting them in terms of velocity.
  • Multiple participants express difficulty in solving the integral \(\int \frac{1}{-g-\alpha \dot{y}^2}\:d\dot{y}\) and discuss various substitution methods that lead to complications.
  • There is a suggestion to use inverse hyperbolic functions such as arctan and arctanh for integration, with differing opinions on which is appropriate.
  • Participants debate the signs of forces acting on the projectile, particularly in relation to gravity and air resistance, and whether they should be considered the same or opposite depending on the direction of motion.
  • One participant claims to have solved the ODE using arctan, while another insists that arctanh should have been used instead, leading to further discussion on the correctness of their approaches.
  • There is a mention of the importance of separating cases for upward and downward motion, with some participants clarifying their assumptions regarding the forces involved.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the correct method for solving the integral or the appropriate use of arctan versus arctanh. There is also disagreement regarding the treatment of forces acting on the projectile during different phases of motion.

Contextual Notes

Participants express uncertainty about the correct integration techniques and the implications of their assumptions regarding the signs of forces. The discussion reflects a variety of approaches and interpretations without resolving the underlying mathematical challenges.

  • #31
P3X-018 said:
Havn't the gravity and aerodynamic forces same signs, when the projectil is on it's way to the top, and on the way down, they have opposite signs?

That's something totally different.I was considering free fall.Yes,the aerodynamics force changes the sign...

Daniel.
 
Physics news on Phys.org
  • #32
P3X-018 said:
Havn't the gravity and aerodynamic forces same signs, when the projectil is on it's way to the top, and on the way down, they have opposite signs?
Precisely!
However, you didn't really make it clear from the start that you were considering BOTH cases; I well understand Daniel's objection (he has worked under the most natural assumption given your info).
 
  • #33
Yea I know it was my fault. I didn't consider the 2 cases, but in the second equation then you got to use arctanh.
 
  • #34
P3X-018 said:
I didn't consider the 2 cases, but in the second equation then you got to use arctanh.

Since partial fraction decomposition disgusts me, go for artanh.
(I guess Daniel has a different view on this..:wink:)
 
  • #35
Take both methods... :-p You'll get the expression for "arctanh" in terms of "ln"...A useful result...A nice proof to it,also...

Daniel.

P.S.Arildno,i LOVE HYPERBOLIC FUNCTIONS... :!) :-p
 
  • #36
Well, but I don't have so much experience in seprating fractions :'(. How do you seprate the fraction
\frac{1}{1\pm u}
 
  • #37
P3X-018 said:
Well, but I don't have so much experience in seprating fractions :'(. How do you seprate the fraction
\frac{1}{1\pm u}
Those can't be decomposed further, but:
\frac{1}{1-u^{2}}=\frac{1}{2}(\frac{1}{1+u}+\frac{1}{1-u})
\frac{1}{1+u^{2}} cannot be partially fractiondecomposed in real partial fractions.
 

Similar threads

  • · Replies 65 ·
3
Replies
65
Views
8K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 14 ·
Replies
14
Views
3K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
Replies
1
Views
1K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 0 ·
Replies
0
Views
3K