Calculating Linear Expansion with Specific Heat Capacity and Mass Density?

Click For Summary
The discussion revolves around calculating linear expansion using specific heat capacity and mass density. The initial attempt at a solution was incorrect, prompting a request for assistance. There is uncertainty regarding whether the heat capacity value of 390 J/K should be interpreted as specific heat capacity of 390 J/(kg K). Clarification on this point could help in utilizing the provided mass density effectively. Accurate interpretation of these values is crucial for solving the problem correctly.
Kara4566
Messages
4
Reaction score
0
Homework Statement
A 1.0m long rod of metal has a diameter of 0.75cm. This metal has
a coefficient of linear expansion α = 4.8 × 10−5 1/K, a density of 9.7 ×10^3 kg/m^3, and heat capacity of 390 J/K.
How much energy needs to be added as heat to increase the length of the rod by 7.5 × 10−3m?
Relevant Equations
change in Length= (Initial Length)(Coefficient of linear expansion)(change in temperature)
242182


Above is my attempt at a solution, however, this did not yield the correct answer. Any help is greatly appreciated!
 
Physics news on Phys.org
I wonder if the heat capacity of 390 J/K is really meant to be a specific heat capacity of 390 J/(kg K). Then, you can make use of the mass density given in the problem.
 
  • Like
Likes Kara4566
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

Similar threads

  • · Replies 2 ·
Replies
2
Views
696
  • · Replies 13 ·
Replies
13
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
Replies
4
Views
1K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
11
Views
5K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 4 ·
Replies
4
Views
9K