Thermal Expansion: Volume vs. Linear - 0.11L Spilled

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SUMMARY

The discussion centers on the thermal expansion of oil and its container when heated from 15°C to 190°C. The linear coefficient of thermal expansion for oil is 0.68 x 10-3, while the pot's coefficient is 2.4 x 10-5. The correct calculation for the spilled oil volume is 0.11 liters, achieved by using the linear expansion formula, despite initial attempts yielding 0.344 liters through volume expansion calculations. This discrepancy highlights the importance of applying the correct coefficients in thermal expansion problems.

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Alex126
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Homework Statement


A one-liter pot is completely filled with oil. Heat is applied to the pot&oil and the temperature rises from 15°C to 190°C. How much oil is spilled over?

The linear coefficient of thermal expansion for oil is 0.68*10-3; the one for the pot is 2.4*10-5

Homework Equations


Linear expansion = starting length * coefficient α * ΔTemperature
Volume expansion = starting volume * coefficient β * ΔT

Coefficient β = 3*α

The Attempt at a Solution


Since we're talking of a pot, and oil in the pot, I thought that we'd be dealing with volume expansion here. So I simply used the formulas, and got the wrong result (0.344 Liters).

Just as an attempt, I then tried doing the exercise with the linear expansion, and got the right (apparently, according to the book) result (0.11 Liters).

What's up with that? Shouldn't it be volume expansion here? The process I thought to be correct was as follows:

V = starting volume (1L)

Oil spilled = [Final oil volume] - [Final pot volume]
Final oil volume = V + volume expansion oil
Final pot volume = V + volume expansion pot
=> oil spilled = volume expansion oil - volume expansion pot

Volume expansion oil/pot = V * βoil/pot * (190-15)
β = 3α

So:
Volume expansion oil = 1*3*0.68*10-3*175 = 0.357
Volume expansion pot = 1*3*2.4*10-5*175 = 0.0126

=> oil spilled = 0.357-0.0126 = 0.344

If I were to "force" the right result (0.11), I would have to use a formula that reads this:

volume expansion = V * linear expansion coefficient * ΔT

Which doesn't make sense to me. So am I missing something, or am I right and the book authors made a mistake and the right answer is 0.344 after all? (Or maybe the error was in the text when they said "linear coefficient" when they actually meant "volume coefficient")
 
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Alex126 said:
(Or maybe the error was in the text when they said "linear coefficient" when they actually meant "volume coefficient")
I think that's the error.

Your thinking is correct. (Look up the coefficient of expansion for oil and check.)
 
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Alright, thanks.
 

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